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- # -*- coding: utf-8 -*-
- #
- # Cipher/PKCS1-v1_5.py : PKCS#1 v1.5
- #
- # ===================================================================
- # The contents of this file are dedicated to the public domain. To
- # the extent that dedication to the public domain is not available,
- # everyone is granted a worldwide, perpetual, royalty-free,
- # non-exclusive license to exercise all rights associated with the
- # contents of this file for any purpose whatsoever.
- # No rights are reserved.
- #
- # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
- # EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
- # MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
- # NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
- # BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
- # ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
- # CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
- # SOFTWARE.
- # ===================================================================
- """RSA encryption protocol according to PKCS#1 v1.5
- See RFC3447__ or the `original RSA Labs specification`__ .
- This scheme is more properly called ``RSAES-PKCS1-v1_5``.
- **If you are designing a new protocol, consider using the more robust PKCS#1 OAEP.**
- As an example, a sender may encrypt a message in this way:
- >>> from Crypto.Cipher import PKCS1_v1_5
- >>> from Crypto.PublicKey import RSA
- >>> from Crypto.Hash import SHA
- >>>
- >>> message = 'To be encrypted'
- >>> h = SHA.new(message)
- >>>
- >>> key = RSA.importKey(open('pubkey.der').read())
- >>> cipher = PKCS1_v1_5.new(key)
- >>> ciphertext = cipher.encrypt(message+h.digest())
- At the receiver side, decryption can be done using the private part of
- the RSA key:
- >>> From Crypto.Hash import SHA
- >>> from Crypto import Random
- >>>
- >>> key = RSA.importKey(open('privkey.der').read())
- >>>
- >>> dsize = SHA.digest_size
- >>> sentinel = Random.new().read(15+dsize) # Let's assume that average data length is 15
- >>>
- >>> cipher = PKCS1_v1_5.new(key)
- >>> message = cipher.decrypt(ciphertext, sentinel)
- >>>
- >>> digest = SHA.new(message[:-dsize]).digest()
- >>> if digest==message[-dsize:]: # Note how we DO NOT look for the sentinel
- >>> print "Encryption was correct."
- >>> else:
- >>> print "Encryption was not correct."
- :undocumented: __revision__, __package__
- .. __: http://www.ietf.org/rfc/rfc3447.txt
- .. __: http://www.rsa.com/rsalabs/node.asp?id=2125.
- """
- __revision__ = "$Id$"
- __all__ = [ 'new', 'PKCS115_Cipher' ]
- from Crypto.Util.number import ceil_div
- from Crypto.Util.py3compat import *
- import Crypto.Util.number
- class PKCS115_Cipher:
- """This cipher can perform PKCS#1 v1.5 RSA encryption or decryption."""
- def __init__(self, key):
- """Initialize this PKCS#1 v1.5 cipher object.
-
- :Parameters:
- key : an RSA key object
- If a private half is given, both encryption and decryption are possible.
- If a public half is given, only encryption is possible.
- """
- self._key = key
- def can_encrypt(self):
- """Return True if this cipher object can be used for encryption."""
- return self._key.can_encrypt()
- def can_decrypt(self):
- """Return True if this cipher object can be used for decryption."""
- return self._key.can_decrypt()
- def encrypt(self, message):
- """Produce the PKCS#1 v1.5 encryption of a message.
-
- This function is named ``RSAES-PKCS1-V1_5-ENCRYPT``, and is specified in
- section 7.2.1 of RFC3447.
- For a complete example see `Crypto.Cipher.PKCS1_v1_5`.
-
- :Parameters:
- message : byte string
- The message to encrypt, also known as plaintext. It can be of
- variable length, but not longer than the RSA modulus (in bytes) minus 11.
-
- :Return: A byte string, the ciphertext in which the message is encrypted.
- It is as long as the RSA modulus (in bytes).
- :Raise ValueError:
- If the RSA key length is not sufficiently long to deal with the given
- message.
- """
- # TODO: Verify the key is RSA
-
- randFunc = self._key._randfunc
-
- # See 7.2.1 in RFC3447
- modBits = Crypto.Util.number.size(self._key.n)
- k = ceil_div(modBits,8) # Convert from bits to bytes
- mLen = len(message)
-
- # Step 1
- if mLen > k-11:
- raise ValueError("Plaintext is too long.")
- # Step 2a
- class nonZeroRandByte:
- def __init__(self, rf): self.rf=rf
- def __call__(self, c):
- while bord(c)==0x00: c=self.rf(1)[0]
- return c
- ps = tobytes(map(nonZeroRandByte(randFunc), randFunc(k-mLen-3)))
- # Step 2b
- em = b('\x00\x02') + ps + bchr(0x00) + message
- # Step 3a (OS2IP), step 3b (RSAEP), part of step 3c (I2OSP)
- m = self._key.encrypt(em, 0)[0]
- # Complete step 3c (I2OSP)
- c = bchr(0x00)*(k-len(m)) + m
- return c
-
- def decrypt(self, ct, sentinel):
- """Decrypt a PKCS#1 v1.5 ciphertext.
-
- This function is named ``RSAES-PKCS1-V1_5-DECRYPT``, and is specified in
- section 7.2.2 of RFC3447.
- For a complete example see `Crypto.Cipher.PKCS1_v1_5`.
-
- :Parameters:
- ct : byte string
- The ciphertext that contains the message to recover.
- sentinel : any type
- The object to return to indicate that an error was detected during decryption.
-
- :Return: A byte string. It is either the original message or the ``sentinel`` (in case of an error).
- :Raise ValueError:
- If the ciphertext length is incorrect
- :Raise TypeError:
- If the RSA key has no private half.
-
- :attention:
- You should **never** let the party who submitted the ciphertext know that
- this function returned the ``sentinel`` value.
- Armed with such knowledge (for a fair amount of carefully crafted but invalid ciphertexts),
- an attacker is able to recontruct the plaintext of any other encryption that were carried out
- with the same RSA public key (see `Bleichenbacher's`__ attack).
-
- In general, it should not be possible for the other party to distinguish
- whether processing at the server side failed because the value returned
- was a ``sentinel`` as opposed to a random, invalid message.
-
- In fact, the second option is not that unlikely: encryption done according to PKCS#1 v1.5
- embeds no good integrity check. There is roughly one chance
- in 2^16 for a random ciphertext to be returned as a valid message
- (although random looking).
-
- It is therefore advisabled to:
-
- 1. Select as ``sentinel`` a value that resembles a plausable random, invalid message.
- 2. Not report back an error as soon as you detect a ``sentinel`` value.
- Put differently, you should not explicitly check if the returned value is the ``sentinel`` or not.
- 3. Cover all possible errors with a single, generic error indicator.
- 4. Embed into the definition of ``message`` (at the protocol level) a digest (e.g. ``SHA-1``).
- It is recommended for it to be the rightmost part ``message``.
- 5. Where possible, monitor the number of errors due to ciphertexts originating from the same party,
- and slow down the rate of the requests from such party (or even blacklist it altogether).
-
- **If you are designing a new protocol, consider using the more robust PKCS#1 OAEP.**
-
- .. __: http://www.bell-labs.com/user/bleichen/papers/pkcs.ps
-
- """
-
- # TODO: Verify the key is RSA
-
- # See 7.2.1 in RFC3447
- modBits = Crypto.Util.number.size(self._key.n)
- k = ceil_div(modBits,8) # Convert from bits to bytes
-
- # Step 1
- if len(ct) != k:
- raise ValueError("Ciphertext with incorrect length.")
- # Step 2a (O2SIP), 2b (RSADP), and part of 2c (I2OSP)
- m = self._key.decrypt(ct)
- # Complete step 2c (I2OSP)
- em = bchr(0x00)*(k-len(m)) + m
- # Step 3
- sep = em.find(bchr(0x00),2)
- if not em.startswith(b('\x00\x02')) or sep<10:
- return sentinel
- # Step 4
- return em[sep+1:]
- def new(key):
- """Return a cipher object `PKCS115_Cipher` that can be used to perform PKCS#1 v1.5 encryption or decryption.
- :Parameters:
- key : RSA key object
- The key to use to encrypt or decrypt the message. This is a `Crypto.PublicKey.RSA` object.
- Decryption is only possible if *key* is a private RSA key.
- """
- return PKCS115_Cipher(key)
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